Question

the critical angle for light going for medium in which wavelength is 4000 angstorm to medium in which its wavelength is 6000 angstrom is​

Answer 1

Answer:

sin-(3/2)

Explanation:

u(refrative index)=c vaccume/c medium

u×c medium = c vaccume

=const.

u1×v1=u2×v2

we know v=nλ

u1×λ1=u2×λ2

u1/u2=λ2/λ1

=6000/4000

=3/2

sinc=u2/u1

sinc=3/2

Answer 2

Explanation:

The law stating that if the direction of a light beam is reversed, despite the number of times the beam is reflected or refracted, it will follow the same path.