Question

The cross section ABCD of a swimming pool is a trapezium. It's width AB = 14 m, depth at the shallow end is 1.5 m and at the deep end is 8m. Find the area of the cross section.

Answer 1

using area of trapezium formula
0.5 x sum of parallel sides x height
the area is 66.5 sq.m

Answer 2

Answer:

The area of cross section is  $66.5 m^2$

Step-by-step explanation:

Given : AB = 14 m

         AD = 1.5 m

        BC = 8 m

To Find : Area of cross section

Solution:

Area of trapezium = $\frac{1}{2} \times \text{Sum of parallel Sides} \times Height$

                                = $\frac{1}{2} \times (AD+BC) \times AB$

                                = $\frac{1}{2} \times (1.5+8) \times 14$

                                = $66.5 m^2$

Hence The area of cross section is  $66.5 m^2$