Math, asked by Anonymous, 6 months ago

The cross – section of a pipe is 400 2

. It is used to fill a hemispherical tank of radius 3 m.

What must be the minimum flow rate of water in the pipe (in cm/sec) so that it can fill up the

tank in less than 20 minutes?​

Answers

Answered by SilverShades67
3

Diameter of the cylindrical pipe = 7cm

∴ radius of pipe r=3.5cm

∴ area of cross section of cylindrical pipe = πr

2

=π(3.5)

2

Rate of water flow = 5 m/s

= 5×10 cm/s

= 500×60 cm/min

= 30000 cm/min

Volume of water discherged per min = π(3.5)

2

×30000cm

3

/min

= 1155000cm

3

/min

Volume of rectangular tank = (4×3×2.31)m

3

= 27.72m

3

= 27720000cm

3

∴ time taken to empty the rectangular tank by the pipe

=

1155000

27720000

min

= 24 min

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