Question

The cross-section of a swimming pool is in the shape of a trapezium. The swimming
pool is 16 m wide at the top and 12 m wide at the bottom and the area of cross-
section is 112 m2. Find the depth of the pool.​

Answer 1

Answer:

114m

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Answer 2

Let depth be h

Given :

• Cross section area : 112m²

• Length of first parallel side : 16m : L1

• Length of second parallel side : 12m : L2

$\sf \: Area = \frac{(l_{</strong><strong>1</strong><strong>} + l_{2}) }{2} \times h \\ \\ \sf112 {m}^{2} = \frac{16 + 12}{2} \times h \\ \\ \sf224 {m }^{2} = 28h \\ \\ \sf \frac{224}{28} = h \\ \\ \red{\sf8m = h}$

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