The cross section of the swimming pool is a trapezium ABCD ab is equal to 16 BC is equal to 5 ad is equal to 75 and length of the pool is 50 metre calculate the volume of the water it hold.
Answers
Answered by
0
Step-by-step explanation:
ANSWER
The cross section of the swimming pool is a trapezium with parallel sides 1.5m and 3m (depth of both ends) and 40m (length of pool) as the ⊥ r distance between ∥ sides.
The width of pool 1.5m can be the length of cross section.
Length of swimming pool=40m
Breadth of the pool=15m
Depth of the pool=1.5m and 3m
∴ Volume of the water=
2
1
[(1.5+3)×40]×15m
3
=
2
1
×4.5×40×15m
3
=1350m
3
Capacity of water in litres =1350×1000litres (1m
3
=1000litres)
=1350000litres
Similar questions