Physics, asked by heyyiam, 1 month ago

The cross-sectional area of end X of a hydraulic jack is 0.005 in and Y is 0.1 m². If a force of 10 N is applied at end X. what is the force that felt at the end Y

Answers

Answered by vkumarsapna

1

Answer:

o.5 newton

Explanation:

f2=a2/a1×f1

f1=.005/.1×10

f1=o.5 newton

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