the cube of 9 CM edge is immersed completely in a rectangular vessel containing water if the dimension of the base are 15 cm and 12 cm find the rise in water level in the vessel
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edge of cube = 9cm
volume of cube = (edge)^3
= (9)^3 = 729cm^3
dimensions of rectangular vessel's are l = 15cm, b = 12cm .
volume water in cube = volume of water in vessel
volume= l × b × h
729 = 15 × 12 × h
729 = 180h
h = 4.05 => h = 4.05cm
rise in water level in the vessel
= 4.05cm
volume of cube = (edge)^3
= (9)^3 = 729cm^3
dimensions of rectangular vessel's are l = 15cm, b = 12cm .
volume water in cube = volume of water in vessel
volume= l × b × h
729 = 15 × 12 × h
729 = 180h
h = 4.05 => h = 4.05cm
rise in water level in the vessel
= 4.05cm
dipikataneja:
ans. is 4.05
........
ya , answer is 4.05 , check it again
thanks for pointing out mistakes
ok
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