the cubes each of side 5 cm are joined in to end find the surface area of resulting cubeoid.
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Answered by
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a=5
then for cuboid
l= 10
b=5
h=5
surface area of cuboid=2(lb+bh+hl)
- 2(10*5+5*5+10*5)
- 2(50+25+50)
- 2(125)
- 250
hope this will help you
if there is calculation mistake then plz forgive me
thanks
Answered by
0
surface area of 1 cube = 6a^2
where, a= 5cm.
s.a. of cube=6× 5×5
=150 cm^2
when 2 cubes are joined to the end
then resultant surface area= 2(6a^2) - 2a^2
= 2×150 - 2×5×5
= 300- 50
S.A. OF CUBOID = 250 cm ^2
ANS.
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