The cubical box has mass of 7200g.the pressure exerted by it on the surface it is placed will be?(g=10m/s²)
VedaantArya:
The side of the cubical box is required for that.
3cm
Sorry 3m
If you could, please edit that into the question.
I've written an answer.
I've written an answer.
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Mass of the box = 7200 g = 7.2 kg.
The total force exerted by the box on the surface is equal to its weight (or the normal contact force) = mass * g = 7.2 kg * 10 m/s² = 72 N.
The area of contact is the area of the bottom face, since it's in contact = side² = 3 m * 3 m = 9 m².
Now, pressure is defined as force/area.
So, pressure = 72 N / 9 m² = 8 N/m² or 8 Pa.
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