Physics, asked by kumarshhhhgggg90, 1 year ago

The current flowing though 3ohm resostor is 0.8amperes,the potential drop across the 4ohm resistor is

Answers

Answered by Ajgenius

please delete my answer

harsharya2123: Voltage across the 3 Ω is E = IR = 3•0.8 = 2.4 volts.

that same voltage is across the 6Ω so the current thu that is I = E/R = 2.4/6 = 0.4 amps

those two currents add to 1.2 amps, which is the current thru the 4 Ω, so the voltage across it is E = IR = 1.2 x 4 = 4.8 volts.

Answered by Anonymous

If the current flowing through the 3Ω resistor is 0.8 A, what will be the potential which drops across the 4Ω resistor?

If 0.8A is flowing through the 3Ω resistor, that means 0.8A is flowing through the other 3Ω resistor. This is because they are in parallel and the same resistance value. As a result, you have a combined 1.6A going through the 4Ω resistance.

By Ohm’s Law,

V = I*R

therefore V = 1.6A * 4Ω

= 6.4 Volts dropped across the 4Ω resistor.

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