Question

The current flowing through a resistor connected in an electric circuit and potential difference across its end are connected to an ammeter and a Voltmer. Find the least count Of the voltmeter and ammeter

Answer 1

Answer:

LC of ammeter = 0.2/10 A = 0.02 A

LC of Voltmeter = 1/10 = 0.1 V

Current = 15 x 0.02 A = 0.3 A

Potential difference = 21 x 0.1 V = 2.1 V

Explanation:

Hope it's Help you

Answer 2

Answer:

LC of ammeter = 0.2/10 A = 0.02

LC of Voltmeter = 1/10 = 0.1 V

Current = 15 x 0.02 A = 0.3 A

Potential difference = 21 x 0.1 V = 2.1 V