The current flowing through a
wire of resistance 212 varies
with time as shown in figure
alongside. The amount of heat
produced
(in J) in 3 s would be
(a) 2J
(b) 18 J
(c) 28 J
(d) 10 J
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Answer:
answer is option C
Explanation:
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Answer:
28 J
Explanation:
we know H=I×I×R×T
Therefore In first second H=3×3×2×1=18J
in second second, H=2×2×2×1=8J
in third second, H=1×1×2×1=2J
total =18+8+2=28J
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