The current i through a conductor varies with time
t as shown in figure. The average electric current
during t = 0 to t = 10 s will be
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The current i through a conductor varies with time t as shown in figure.
To find : The average electric current during 0 ≤ t ≤ 10s will be
solution : total charge = area enclosed by the current - time graph
= area of trapezium - area of triangle (which is formed below x - axis)
= 1/2 × (8 + 4) × 8 - 1/2 × 2 × 8
= 12 × 4 - 8
= 48 - 8
= 40C
total time = 10s
so the average electric current = total charge/total time
= 40C/10s
= 4 C/s = 4 Ampere
Therefore the average electric current during 0 to 10s will be 4 A.
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