Question

The current in a coil is changed from 5A to 10A in 10²s an emf of 50mV is induced in coil near by it the mutual inductance of two coils is

Answer 1

Answer:

As we know that,

e=M×di/dt

Here, EMF=50×10^-3v

Change in time,dt=100sec

change in current,di=10-5=5A

Where,M is the mutual inductance

e=M×di/dt

50×10^-3=M×5/100

M=10²×10^-2

M=1H

Explanation:

Hope it helps you..