the current in the windings on a toroid is 2.0 a there are 400 turns and the mean circumferential length is 40 cm if the inside magnetic field is 1.0 Tesla the relative permeability is near about
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Answer:
Toroid
B=
2πr
μ
0
Ni
in free space
B=
2πr
μ
0
μ
r
Ni
in a medium
Given: i=2 A
N=400 turns
circumferential length =2πr=40 cm=0.4 m
B=I T
substituting the values in formula;
I=
0.4
μ
r
μ
0
(400)(2)
. also μ
0
=4π×10
−7
hence μ
r
=
4π×10
−7
×400×2
0.4
=400
hence
μ
r
=400
Explanation:
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