Math, asked by sanjeevkhajuria, 20 days ago

The current population of a city is 26010. It grows at a rate of 2% each year.
What was the population of the city 2 years ago ?
(b) 25100
(c) 25200 (d) 25500
(a) 25000​

Answers

Answered by 12thpáìn
240

Given

  • Present Population= 26010
  • Growth Rate= 2%
  • Time= 2 years

To Find

  • Total population after 2 years ago

Formula used

 \mathtt{Amount= P×\left( 1 - \cfrac{r}{100}\right) ^n}

Where

  • Amount= Total population
  • Principal= Present Population
  • R stand for Rate
  • T stand for Time

Putting the Value of Principal,Rate and Time

In formula

\mathtt{Amount= 26010×\left( 1 - \cfrac{2}{100}\right) ^2}

\mathtt{Amount= 26010×\left( \cfrac{100  - 2}{100}\right) ^2}

\mathtt{Amount= 26010×\left( \cfrac{98}{100}\right) ^2}

\mathtt{Amount= 26010×\left( \cfrac{49}{50}\right) ^2}

\mathtt{Amount= 26010× \cfrac{2401}{2500} }\\

\mathtt{Amount= 10.404 \times 2401 }\\

\mathtt{Amount= 24980 }\\

  • Total population after 2 years ago= 24980
Answered by badolamamta68
4

Step-by-step explanation:

answer is in the attachment

hope this helps you

Attachments:
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