Question

The current through a bulb filament if 2.5A. The
heat generated in 40 min is 24 KJ Find the resistance
of the filament.

...​

Answer 1

Explanation:

Current = 4A

Resistance = 40Ω

time = 8×60 second

Heat = i

2

Rt

=16×40×8×60

=

1000

16×24×8×10

2

×1000

= 307.2 K Joules