Question

The current through a wire depends on time as, i=(10+4t) Here , i is ampere and t in seconds. Find the charge crossed through section in time interval between t=0 to t=10s.

Answer 1

Answer:

500Couloumb

Explanation:

by definition

I=dQ/dt

hence Q=integral of current with respect to time

on solving this we get answer

Answer 2

Given,

i=10+4t A

●Current is vary with respect to time

As we know, current is change in the charge with respect to time.

t=0s to t=10s

●Since, i=dQ/dt

dQ= idt

Integrating both side with time t=0s to t=10 s

Integration of dQ = integration of i dt(upperlimit 10 ,and lower limit 0)

Q=Integration of 10+4t[10 ,0]

=10×10+2×100=500 C

Hence ,the charge crossed =500C