Question

The current through a wire is connected to a condenser varies with tone as I=(2t + 1)A.
The charge transport to the condenser from t=0 to t=5s is?? Guys please answer this is urgent. Explain with steps. Thank you in adv

Answer 1

here, current flows through a wire is connected to a condenser varies with time as I = (2t + 1)A

we know , current is rate of change of charge . e.g., I = ∆Q/∆t

so, at any instant of time, i = dQ/dt

so, I = dQ/dt = (2t + 1)

or, $\int\limits^Q_0 dQ=\int^5_0{(2t+1)}\,dt$

or, Q = $\left[t^2+t\right]^5_0$

or, Q = (5² + 5) = 25 + 5 = 30C

hence, charge transport to the condenser from t = 0 to t = 5 sec is 30C.