the curved suface area of a right cirrcular cylinder of height 14 cm is 88cm find the diameter of the base of the cylinder
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
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csa=88
2πrh=88
2×22/7×r×14=88
r={88×7}/{44×4}
r=1cm
diameter=2r=2×1=2cm=0.02m
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2πrh=88
2×22/7×r×14=88
r={88×7}/{44×4}
r=1cm
diameter=2r=2×1=2cm=0.02m
thanks
please mark me brainliest
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