the curved surface area of a cylinder kal pillar is 528 metres square and its volume is 277 to metre cube find the diameter and the height of the pillar
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According to question
2 pi *r*h=528----------------(1)
pi * r^2 *h = 277 ------------(2)
On dividing equation 1 by equation 2,we get
2/r=528/277
1/r = 264/277
r=277/264
Now, Putting the value of r in equation (1)
(2*22*277*h)/7*264 =528
=> 44*277*h =528*264/7
=> h = (12*264)/(7*277)
=> h = 3168/1939
2 pi *r*h=528----------------(1)
pi * r^2 *h = 277 ------------(2)
On dividing equation 1 by equation 2,we get
2/r=528/277
1/r = 264/277
r=277/264
Now, Putting the value of r in equation (1)
(2*22*277*h)/7*264 =528
=> 44*277*h =528*264/7
=> h = (12*264)/(7*277)
=> h = 3168/1939
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