Question

the curved surface area of a cylinder of height 5cm is 440 cm².find the radius of the base​

Answer 1

Given:-

• The curved surface area of a cylinder of height 5cm is 440 cm².

To Find:-

• Find the radius of the base.

Concept:-

• Firstly let's go through the concept. Concept used here is Curved Surface Area (CSA) of a Cylinder.Substitute the values in the equation and solve it.

Formulae Applied:-

• Curved Surface Area (CSA) of a cylinder = 2πrh

Solution:-

Given that,

The curved surface area of a cylinder of height 5cm is 440 cm².

Let the radius of the cylinder be r

According to the question we have,

Curved Surface Area (CSA) of a cylinder = 2πrh

= 2πrh

= 2πrh = 440

= 2 × 22/7 × r × 5 = 440

= 44/7 × 5r = 440

= 5r = 440 ×7/44 = 70

= 5r = 70

= r = 70/5

= r = 12

Hence,

The radius of the base is 12.

Answer 2

☆QUESTION :

The curved surface area of a cylinder of height 5cm is 440 cm². Find the radius of the base​ .

☆ANSWER :

 $\bf\bullet$  The curved surface area of cylinder is given as 440 cm².

 $\bf\bullet$ Height of the cylinder = 5 cm.

We need to find the radius of the base of the cylinder.

As we know that ,

The curved surface area of a cylinder = 2πrh .

$\huge{\boxed{\bf{CSA\:of\:a \:cylinder=2\pi\:rh}}}}}}$

Let the radius of the base be ' X ' .

On substituting the values ,

CSA of a cylinder = 440 cm²  =  2πrh

           $\bf{ 440 \: cm^2 = 2 \:x\: \pi\: x \:X\: x\: 5}$

              $\bf{440 = 2 \:x \:\dfrac{22}{7 }\:x\: X\: x\: 5}$

              $\bf{440 = \dfrac{44}{7} (5X)}$

              $\bf{\dfrac{440\:x\:7}{44}=5X}$

               $\bf{10\:x\:7=5X}$

                $\bf{5X=70}$

                $\bf{X=\dfrac{70}{5}}$

               $\bf{X=12}$

Here,

X = Radius of the base of the cylinder.

∴ The radius of the cylinder = 12 cm.

           

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