Question

The curved surface area of a right circular cylinder of height 14cm is 88cm2.Find the diameter of the base of the cylinder. Show the process.

Answer 1

height of the cylinder =h = 14cm
let radius of the base = r cm

curved surface area =CSA = 2πrh
this is equal to 88cm² given in the problem

2πrh = 88
2*22/7*r*14 =88

2*22*2*r =88 [ after cancellation]

88r = 88
r = 88/88
r =1 cm
therfore

diameter (d) = 2r=2*1cm = 2cm

Answer 2

$h = 14cm$

$r = \: ?$

$csa = 2\pi \: r \: h = 88$

$2 \times \frac{22}{7} \times r \times 14 = 88 \\ 44 \times r \times 2 = 88 \\ 88r = 88 \\ r = \frac{88}{88} \\ r = 1cm$

$d = 2r \\ = 2 \times 1 \\ = 2cm$

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