Math, asked by Anonymous, 11 months ago

the curved surface area of cylinder pillar is 264 metre square and its volume is 924 cm cube find the diameter and the height of pillar​

Answers

Answered by usharmavn
9

Answer:

Step-by-step explanation:

we know that the curved surface area of a cylinder is 2\pirh and the volume is

\pi(r^2)h

therefore using the same we have

\pi r^{2}h=924 cm^{3} -----------  1

2\pirh = 264 -----------------2

dividing equation 1 by 2 we get

r/2 = 3.5

r = 7 and diameter is = 2r = 2 x 7 = 14cm.

putting this value in equation 2 we get

2 x 22/7 x 7 x h = 264

h = 6

CHEERS MATE, PLEASE MARK BRAINLIEST

Answered by Anonymous
32

\huge\underline\frak\purple{Given:-}

The curved surface area of cylinder pillar is 264 metre square and its volume is 924 cm³

\huge\underline\frak\purple{To\:find:-}

Find the diameter and the height of pillar

\huge\underline\frak\purple{Solution:-}

\large{\boxed{\bf{\red{Method\::1}}}}

As we know that

Curved surface area of cylindrical pillar

\sf 2πrh=264m^2 ---(i)

Volume of cylinder pillar

\sf πr^2h=924m^3 ------(ii)

Divide (ii) by (i)

\implies\sf \frac{πr^2h}{2πrh}=\frac{924}{264}

\implies\sf \frac{r}{2}=\frac{924}{264}

\implies\sf r=\frac{2×924}{264}

\implies\sf r=7m

Substitute the value of r in equation (i)

\implies\sf 2πrh=264

\implies\sf 2×\frac{22}{7}×7×h=264

\implies\sf 44h=264

\implies\sf h=\cancel\frac{264}{44}=6m

\large{\boxed{\bf{Required\:diameter=2×7=14m}}}

\large{\boxed{\bf{Required\:height=6m}}}

\large{\boxed{\bf{\red{Method\::2}}}}

Curved surface area of cylindrical pillar

\implies\sf 2πrh=264

\implies\sf πrh=\cancel\frac{264}{2}=132m^2----(i)

Volume of cylindrical pillar

\implies\sf πr^2h=924

we can write in this way also

\implies\sf r(πrh)=924

Substitute the value of πrh from (i)

\implies\sf 132r=924

\implies\sf r=\cancel\frac{924}{132}=7m

To find the value of height , we need to substitute the value of r in equation (i)

\implies\sf πrh=132

\implies\sf \frac{22}{7}×7×h=132

\implies\sf h=\cancel\frac{132}{22}=6m

\large{\boxed{\bf{Required\:diameter=2×7=14m}}}

\large{\boxed{\bf{Required\:height=6m}}}

\huge\underline\frak\green{Note}

★Curved surface area of cylinder★

= 2πrh

★Volume of cylinder ★

= πr²h

★Total surface area of cylinder★

= 2πrh+2πr²

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