Math, asked by Anonymous, 1 year ago

the curved surface area of cylinder pillar is 264 metre square and its volume is 924 cm cube find the diameter and the height of pillar​

Answers

Answered by usharmavn
9

Answer:

Step-by-step explanation:

we know that the curved surface area of a cylinder is 2\pirh and the volume is

\pi(r^2)h

therefore using the same we have

\pi r^{2}h=924 cm^{3} -----------  1

2\pirh = 264 -----------------2

dividing equation 1 by 2 we get

r/2 = 3.5

r = 7 and diameter is = 2r = 2 x 7 = 14cm.

putting this value in equation 2 we get

2 x 22/7 x 7 x h = 264

h = 6

CHEERS MATE, PLEASE MARK BRAINLIEST

Answered by Anonymous
32

\huge\underline\frak\purple{Given:-}

The curved surface area of cylinder pillar is 264 metre square and its volume is 924 cm³

\huge\underline\frak\purple{To\:find:-}

Find the diameter and the height of pillar

\huge\underline\frak\purple{Solution:-}

\large{\boxed{\bf{\red{Method\::1}}}}

As we know that

Curved surface area of cylindrical pillar

\sf 2πrh=264m^2 ---(i)

Volume of cylinder pillar

\sf πr^2h=924m^3 ------(ii)

Divide (ii) by (i)

\implies\sf \frac{πr^2h}{2πrh}=\frac{924}{264}

\implies\sf \frac{r}{2}=\frac{924}{264}

\implies\sf r=\frac{2×924}{264}

\implies\sf r=7m

Substitute the value of r in equation (i)

\implies\sf 2πrh=264

\implies\sf 2×\frac{22}{7}×7×h=264

\implies\sf 44h=264

\implies\sf h=\cancel\frac{264}{44}=6m

\large{\boxed{\bf{Required\:diameter=2×7=14m}}}

\large{\boxed{\bf{Required\:height=6m}}}

\large{\boxed{\bf{\red{Method\::2}}}}

Curved surface area of cylindrical pillar

\implies\sf 2πrh=264

\implies\sf πrh=\cancel\frac{264}{2}=132m^2----(i)

Volume of cylindrical pillar

\implies\sf πr^2h=924

we can write in this way also

\implies\sf r(πrh)=924

Substitute the value of πrh from (i)

\implies\sf 132r=924

\implies\sf r=\cancel\frac{924}{132}=7m

To find the value of height , we need to substitute the value of r in equation (i)

\implies\sf πrh=132

\implies\sf \frac{22}{7}×7×h=132

\implies\sf h=\cancel\frac{132}{22}=6m

\large{\boxed{\bf{Required\:diameter=2×7=14m}}}

\large{\boxed{\bf{Required\:height=6m}}}

\huge\underline\frak\green{Note}

★Curved surface area of cylinder★

= 2πrh

★Volume of cylinder ★

= πr²h

★Total surface area of cylinder★

= 2πrh+2πr²

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