Question

The curved surface area of frustum of a cone is given by

Answer 1

The curve surface area of frustum of a cone is given by,

$\textbf{curve surface area}=\pi(R+r)l$

where R is radius of bigger circular end of frustum and r is the smaller circular end of frustum. l is lateral length of frustum.

Let height of frustum is h.

then, $l=\sqrt{h^2+(R-r)^2}$

so, curve surface area of frustum = $\pi(R + r)\sqrt{h^2+(R-r)^2}$

Answer 2

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$\Large\fbox{\color{purple}{QUESTION}}$

SURFACE AREA VOLUME FORMULAS

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$\Large\fbox{\color{purple}{ SOLUTION }}$

$\Large\mathcal\green{FRUSTUM}$

$\implies \: tsa = \pi \: l(r1 + r2) + \pi \: {r1}^{2} + \pi {r2}^{2}$

$\implies \: csa = \pi \: l(r1 + r2)$

$\implies volume = \frac{1}{3}\pi \: h( {r1}^{2} + r1.r2 + {r2}^{2} )$

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