Math, asked by mds663157, 4 months ago

The curved surface of a solid metalic sphere is cut in such a way that the curved sur
area of the new sphere is half of that previous one. Let us calculate the ratio of the volume
to make the two spheres.
of the portion cut off and the remaining portion of the sphere.​

Answers

Answered by kanhaiyakumarks88
0

Answer:

hlo....... good morning....to all

Answered by taehyung21
0

Answer:

\huge\mathfrak\pink{✩Answer☆}

Let the radius of the old sphere be =R unit

let the radius of the new sphere be =r unit

therefore,curved surface area of the old sphere =4πR²

and the curved surface area of the new sphere =4πr²

______________________

ATP,

4πR²/2=4πr²

or,R²=2r²

or ,R²=√2r²

or,R²=√2r

_______________________

now,volume of the old sphere=4/3πr³=4/3(2r)³ cubic unit

volume of the new sphere=4/3πr³

_______________________

volume of the remaining sphere =4/3(√2 r)³-4/3 πr³

⠀⠀ ⠀⠀ ⠀ ⠀⠀ ⠀⠀ ⠀⠀ ⠀⠀ ⠀ =4/3π³(2√2-1)

therefore,the ratio of the cut off portion and remaining part =4/3πr³:4/3πr³(2√2-1)

=1:2√2-1 (ANS)

____________________..____________________

hope this helps you.

Similar questions