Math, asked by racesf, 11 months ago

the curvedsurface area of a right circular cylinder of height 14cm is 176cm².the diameter of the base is ​

Answers

Answered by Anonymous
31

Given :

  • The curved surface area of a right circular cylinder is 176 cm².
  • Height of the cylinder = 14 cm

To find :

  • Diameter of the base.

Solution :

Consider,

  • Radius of the cylinder = r cm
  • Diameter of the cylinder = 2r cm

Height of cylinder ( h) = 14 cm

Formula Used :-

{\boxed{\bold{CSA\:of\: cylinder=2\pi\:rh}}}

\to\sf{CSA=2\times\dfrac{22}{7}\times\:r\times\:14\:cm^2}

\to\sf{CSA=88r\:cm^2}

{\underline{\sf{According\:to\: the\: question:-}}}

\mapsto\sf{88r=176}

\mapsto\sf{r=\dfrac{176}{88}}

\mapsto\sf{r=2}

  • Radius = 2 cm

Diameter of the base = 2r

→ Diameter of the base = ( 2 × 2 ) cm

→ Diameter of the base = 4 cm

Therefore, diameter of the base is 4 cm.

Answered by Anonymous
96

Qᴜᴇsᴛɪᴏɴ

➥ The curvedsurface area of a right circular cylinder of height 14 cm is 176 cm².the diameter of the base is

Aɴsᴡᴇʀ

➥ Diameter of the base = 4 cm

Gɪᴠᴇɴ

➥ C.S.A = 176 cm²

➥ Height = 14 cm

Tᴏ Fɪɴᴅ

➥ Diameter of the base = ?

⠀⠀⠀

According To Given Question

⠀⠀⠀

↗ Let r be the radius and h be the height of cylinder

❈ As we know that the formula for finding the value of C.S.A is ፦

\displaystyle{:\implies\bf{2\pi rh}}

⤵ On putting the value of formula, we get

 \displaystyle {\sf{: \implies 2 \times  \frac{22}{ \cancel{ \: 7 \:  }}  \times  \cancel{14} = 176}} \\  \\  \sf{: \implies 2 \times 22 \times 2 = 176}\\  \\  \sf{: \implies 88r = 176 }   \\  \\  \sf{: \implies r =  \frac{ \cancel{176}}{ \cancel{88}} } \\  \\  \sf{: \implies  \bf{ \underline{ \boxed{ \green{ \bf{ \:  \: r = 2 \: cm \:  \: }}}}}}\\  \\  \rm{ \underline{Now,}}

❈ As we know that the formula for finding the value of diameter is ፦

\sf{ : \implies\bf{ Diameter = 2r}}

⤵ On putting the value of formula, we get

 \sf{ : \implies Diameter\: of \:the \:base= 2 \times 2} \\  \\ \sf{ : \implies Diameter \: of \: the \: base = \underline{\boxed{ \bf{ \purple{ \:  \:  4 \: cm \:  \: }}}}}

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