The cyclic hydrocarbon(a) has a molecular formula of c6h6.It is a planar molecule.In a all the c-c bonds have the same bond length.Then the angle c-c-c is
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In benzene all 'c'- atoms are
sp2 hybridized and they also exhibit resonance .
Explanation:
It shows partial double bond character, as it's bond length is intermediate between C=C(1.34A0) and C-C(1.54A0)
The actual structure of benzene is a hybrid, with six delocalised π-electrons.
This structure explains it's stability and low reactivity.
All C-C bonds show sp2−sp2 overlap sideways to form three π- bonds
Resonance hybrid shows properties of all possible resonating structures with intermediate values.
Resonance concept is purely hypothetical, yet, it helps.
The bond length in benzene ring is 1.39A0
sp2 hybridized and they also exhibit resonance .
Explanation:
It shows partial double bond character, as it's bond length is intermediate between C=C(1.34A0) and C-C(1.54A0)
The actual structure of benzene is a hybrid, with six delocalised π-electrons.
This structure explains it's stability and low reactivity.
All C-C bonds show sp2−sp2 overlap sideways to form three π- bonds
Resonance hybrid shows properties of all possible resonating structures with intermediate values.
Resonance concept is purely hypothetical, yet, it helps.
The bond length in benzene ring is 1.39A0
Answered by
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HEY MATE!
HERE IS YOUR ANSWER:
C6H6 is a BENZENE which forms a hexagone.
Each angle in a hexagon is 120°
Hence c-c-c angle ia also 120°.
____________________☆☆
HOPE IT HELPED ^_^
HERE IS YOUR ANSWER:
C6H6 is a BENZENE which forms a hexagone.
Each angle in a hexagon is 120°
Hence c-c-c angle ia also 120°.
____________________☆☆
HOPE IT HELPED ^_^
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