Question

The cylindrical tube of a spray pump has radius, R, one end
of which has n fine holes, each of radius r. If the speed of the
liquid in the tube is V, the speed of the ejection of the liquid
through the holes is : [2015 RS]
(a)VR²/nr²
(b)VR²/n³r²
(c)V²R/nr
(d)VR²/n²r²

Answer 1

Explanation:

Using equation of continuity, Av=constant

A

1

v

1

=A

2

v

2

∴πR

2

V=(nπr

2

)v

′

where nπr

2

is the total area of n fine holes.

⇒v

′

=

nr

2

VR

2

Answer 2

Answer:

its answer is....

Explanation:

VR² / N² R²

HOP.....