the cylindrical vessel with diameter 42 CM contains sufficient water to submerge a rectangular solid of iron of dimensions 24 cm X 16.5 CM x 12 cm find the rise in the level of water when the solid is completely submerged
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i thnk 3.42cm hope so
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Orignal formula of volume of anything = area of base × height .
Using above formula we get Volume of risen part = πr² × h
=> (1386 × h) cm³
But volume of rectangular solid
=>24×16.5×12 = 4752 cm³
Now volume of risen water part = Volume of rectangular solid
So we get ;
=>1386 × h = 4752
=>h = 4752 upon 1386
=> h = 3.428cm or can be written as 3.43cm
Using above formula we get Volume of risen part = πr² × h
=> (1386 × h) cm³
But volume of rectangular solid
=>24×16.5×12 = 4752 cm³
Now volume of risen water part = Volume of rectangular solid
So we get ;
=>1386 × h = 4752
=>h = 4752 upon 1386
=> h = 3.428cm or can be written as 3.43cm
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