Chemistry, asked by scilakshmipriya, 8 months ago

the d electron configuration of [Ru(en)3] cl2 &Fe[(H2O)6]Cl2 respectively are

Answers

Answered by monikareddycr143

Explanation:

water and ferrous treated as finally

Attachments:

Answered by rishikeshm1912

In complex [Ru(en)₃]Cl₂, metal Ru is in +2 state. Metal Ru belongs to 4d-series thus en group behave as strong field group. Therefore, en group will behave as low spin group which means pairing of electrons in d orbital will take place.
So, electronic configuration of Ru⁺² is [Kr] 4d⁶.
Therefore, d electronic configuration of Ru⁺² in complex [Ru(en)₃]Cl₂ is t₂g⁶ eg⁰.
In complex [Fe(H₂O)₆]Cl₂, metal Fe is in +2 state. Metal Fe belongs to 3d-series thus H₂O group behave as weak field group. Therefore, H₂O group will behave as high spin group which means pairing of electron is absent in d orbital.
So, electronic configuration of Fe⁺² is [Ar] 3d⁶.
Therefore, d electronic configuration of Fe⁺² in complex [Fe(H₂O)₆]Cl₂ is t₂g³ eg².

Previous Question

Next Question