Chemistry, asked by scilakshmipriya, 5 months ago

the d electron configuration of [Ru(en)3] cl2 &Fe[(H2O)6]Cl2 respectively are​

Answers

Answered by monikareddycr143
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Explanation:

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Answered by rishikeshm1912
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d electronic configuration of [Ru(en)₃]Cl₂ and [Fe(H₂O)₆]Cl₂

Explanation:

  • In complex [Ru(en)₃]Cl₂, metal Ru is in +2 state. Metal Ru belongs to 4d-series thus en group behave as strong field group. Therefore, en group will behave as low spin group which means pairing of electrons in d orbital will take place.
  • So, electronic configuration of Ru⁺² is [Kr] 4d⁶.
  • Therefore, d electronic configuration of Ru⁺² in complex [Ru(en)₃]Cl₂ is t₂g⁶ eg⁰.
  • In complex [Fe(H₂O)₆]Cl₂, metal Fe is in +2 state. Metal Fe belongs to 3d-series thus H₂O group behave as weak field group. Therefore, H₂O group will behave as high spin group which means pairing of electron is absent in d orbital.
  • So, electronic configuration of Fe⁺² is [Ar] 3d⁶.
  • Therefore, d electronic configuration of Fe⁺² in complex [Fe(H₂O)₆]Cl₂ is t₂g³ eg².
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