Question

The daily coast of milk (in Rs) supplied to 25 houses in
locality are given below
cost (in rs)
40 - 50
50 - 60
60 - 70
70 - 80
80 - 90
90 - 100

If one house is chosen at random find the probability that :
a) The milk bill of the house lies between Rs 60 and Rs. 80
b) house is playing at the most Rs 69. for the milk bill
c) The milk bill of the house is below Rs. 50.​

Answer 1

Answer:

8/25,12/25

Step-by-step explanation:

number of favourable cases= (60,70) and (70,80) as milk bill lies between 60 and 80. Hence number of favourable houses

3 + 5.

8. =

total number of cases= total number of houses= 25.

P(bill is between 60 and 80) = number of favourable cases/ total cases=8/25

ii) number of favourable cases= (40,50), (50,60), (60,70).

= 4 + 5 +3

= 12.

(60,70) is also included because range (60,70) is actually (60,69)

this follows for all ranges for example (40,50) is actually range (40,49) because 50

is included in (50,60).

total number of cases=25.

P(houses paying at most 69 Rs for bill)= 12/25

Hope it helps

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