Math, asked by bmuri580, 19 days ago

The daily consumption of milk in excess of 20000 gallons is approximately distributed as a gamma variable with parameter alpha=2 and Lambda=1/3000.The city as daily stock of 30000 gallons.what is the probability that out of two days random selected the stock is sufficient on particular day.

Answers

Answered by dakshkumarryanris
2

Answer:

14

Step-by-step explanation:

Answered by sadiaanam
1

Answer:

Therefore, the probability that the milk is sufficient for both the days if two days are selected at a random = ( e 10)2 = e -10 or 14

Step-by-step explanation:

If the random variable x denotes the daily consumption of milk in a city , then y=x- 10000 has exponential distribution with mean Ф = 1000

mean = 1/x = 1000= x 1/1000

g(y)=1/1000 - e -y/1000 , 0<y<∝

since the daily stock of the city is 20000 gallons , the probability that the stock is insufficient on a particular day,

 = p(x>20000)

= p(y > 10000)     = { 1/3000 e dy}

[-e  -y/3000]

= -(0-e -10)= e -10

therefore, the probability that the milk is sufficient for both the days if two days are selected at a random = ( e 10)2 = e -10 or 14

https://brainly.in/question/48566650

#SPJ3

Similar questions