Question

the de borgile wavelength of a tennis ball if mass 60g moving with a velocity of 10m/s is approximately ​

Answer 1

According to de Broglie's hypothesis, each moving body is associated some wave character. The wavelength associated is,

$l(lamda) = \frac{h}{mv}$

$l = \frac{6.62 \times {10}^{ - 34} }{60 \times {10}^{ - 3} \times 10 }$

$l = 1.1 {e}^{ - 33}$

Answer 2

Answer:-

$\implies \: \boxed{\bf{\lambda \: = {10}^{-33} \: or \: 10 \times {10}^{-34} }}$

Step - by - step explanation:-

To find :-

Find De Broglei's wavelength.

Given :-

Mass(m) = 60 g = 60÷ 1000 kg

Velocity (v)= 10 m/s

Solution :-

We know that,

$\bf{ \lambda \: = \frac{h}{p}}$

$here \: \\ \bf{\lambda \: = de \: broglei '\: s \: wavelength \: }\\ \\ \bf{ h \: = \: plank 's\: constant }\\ \bf{\because \: h \: = 6.6 \times {10}^{-34} } \\ \\ \bf{ p \: = \: momentum = mass \: \times velocity} \\ \\ \therefore \: \bf{\lambda \: = \frac{6.6 \times {10}^{-34} }{ \frac{60}{1000} \times 10} } \\ \\ \implies \: \bf{ \lambda \: = 1.1 \times {10}^{-33} } \\ \\ \implies \: \bf{ \lambda \: = 11 \times {10}^{-34} }$

By round off rule -

$\implies \: \bf{\lambda \: \cong \: 10 \times {10}^{-34} \: = {10}^{-33} }$