Physics, asked by hriatteicolneylalhri, 25 days ago

The de-broglie wavelength af an electron of energy 400ev
a)20A°
b) 60A°
c)0.6A°
d)0.2A°​

Answers

Answered by ahmeddanishmadani
1

Answer:

Energy = 400 eV = 400 *1.6×10^(−19) Joule =6.4*10^(-17)

Energy = Planck’s constant * velocity of light / wavelength

or, Wavelength = Planck’s constant * velocity of light / Energy

or, wavelength = 6.626 * 10^(-34) * 3* 10^8 /6.4* 10^(-17)

or, wavelength = 3.1059375 * 10^(-9) m ~ 3.12 * 10^(-9) m

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