Question

The de broglie wavelength associated with a particle of mass 6 kg with velocity 10 metre per second

Answer 1

Answer:

debroglie's wavelength = h/mv

Explanation:

wavelength = h/ (6 × 10)

wavelength= h/60 where h is planks constant

Answer 2

Answer:

De Broglie wavelength

= h/mv (h is Plank's Constant)

= 6.626 x 10^-34 J.s/ 6 Kg x 10 m/s

= 1.143 x 10^-35 m

Hope it helps!