Question

The De-Broglie wavelength associated with
electrons revolving round the nucleus in a hydrogen
atom in ground state, will be-​

Answer 1

According to Bohr ′s postulate

$mvr = \frac{nh}{2\pi}$

so the momentum in ground state(n=1) will be ,

$p = \: mv \: = \frac{h}{2\pi \: r}$

Required wavelength will be λ

$λ \: = \frac{h}{p} \: = \frac{h}{h/2πr} \:$

$λ = 2\pi \: r$

Value of radius for ground state in hydrogen is

r=0.53Angstrom

Using that we get λ=3.32Angstrom

Answer 2

Answer:

0.53 angstorm

Explanation:

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