Question

The de-broglie wavelength of a particle of mass 6.625 x 10-3 kg. moving with a velocity 2 x 107m/s is

Answer 1

Given

mass m= 6.62×10 -3 kg

velocity v= 2×10ttp 7 m/sec

now Planck's constant h =6.62×10 ttp -34 j-s

now By de Broglie wavelength eqn

lemda = h/p
= h/mv
=6.62×10 ttp -34/6.62 ×10ttp -3×2×10ttp7
=0.5×10ttp -34 -4
= 5×10 ttp -39 m Ans

Hope it helps