Question

The decimal expansion of rational number 37/2^2×5 will terminate after how many decimal places?

Answer 1

We have 37/(2^2x 5) = 37x5/(2^2x 5^2) = 185/100 = 1.85

Now if a number is of type, n/(2^a x 5^b) where n is not a multiple of 2 or 5, then the number of digits after zero in this number will be either a and b, whichever is greater.

Answer 2

Answer:We have 37/(2^2x 5) = 37x5/(2^2x 5^2) = 185/100 = 1.85

Now if a number is of type, n/(2^a x 5^b) where n is not a multiple of 2 or 5, then the number of digits after zero in this number will be either a and b, whichever is greater.

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Step-by-step explanation:We have 37/(2^2x 5) = 37x5/(2^2x 5^2) = 185/100 = 1.85

Now if a number is of type, n/(2^a x 5^b) where n is not a multiple of 2 or 5, then the number of digits after zero in this number will be either a and b, whichever is greater.

Read more on Brainly.in - https://brainly.in/question/5258308#readmore