Chemistry, asked by maga40, 5 days ago

The decomposition of hydrogen lodide 2HI—>H2+I2 has rate contant 9.51x10-9 molLs at 500k and 1. 10x10-5 molLs at 600k. Calculate energy of activation?

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Answered by ushamahadeva910

0

Answer:

i am not getting did anyone get it

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