Chemistry, asked by paro326, 1 year ago

The decomposition of phosphine ph3 proceeds according to the equation

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Answered by 217him217
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Explanation:

Decomposition of phosphine (PH3) at 120o proceeds according to the equation: 4PH3 (g) ---------- P4 (g) + 6H2 (g) It is found that this reaction follows the following rate equation: Rate = k [PH3] The half life of PH3 is 37.9 s at 120oC

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