The eccentricity of the hyperbola whose latus rectum is half of its transverse axis, is
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Answer:
Given latus rectum = 12× Conjugate axis
2b2a=12×2b
2b=a
b2=a2(e2−1)
b2=4b2(e2−1)
1/4=e2−1
e2=1+14=5/4
e=√5/2
Hence √5/2 is the correct answer
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