Question

The deflection produced in a
galvanometer is reduced to 45 division
from 55 when a shunt of 8 ohm ib used.
Calculate the resistance of the
galvanometer.​

Answer 1

Given that,

Current through galvanometer $I_{g}= 55$

Current through galvanometer after shunt $I_{g}'= 45$

Shunt resistance = 8 ohm

We need to calculate the current through shunt

Using formula of current

$I_{s}=I_{g}-I_{g}'$

Put the value into the formula

$I_{s}=55-45$

We need to calculate the resistance of the  galvanometer

Using formula of parallel current distributes in increase ratio of resistance

$\dfrac{I_{G}}{I_{S}}=\dfrac{S}{G}$

$G=\dfrac{I_{s}}{I_{G}}\times S$

Put the value into the formula

$G=\dfrac{55-45}{45}\times8$

$G=1.78\ \Omega$

Hence, The resistance of the  galvanometer is 1.78 Ω.

Answer 2

Explanation:

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