Question

The degree of dissociation of 0.1m of ch3cooh will be equal to

Answer 1

Answer:

See below.

Explanation:

The dissociation constant of acetic acid ( found in NCERT book ) is,

$K_{a}=1.74\times 10^{-5}$

The degree of dissociation ( alpha ) is given by,

$K_{a}=\alpha ^{2}c$

where C is the molar concentration.

Therefore,

$\begin{aligned}\alpha=\sqrt {\dfrac {K_{a}}{c}}\\ =\sqrt {\dfrac {1.74\times 10^{-s}}{0.1}}=1:32\times 10^{-2}\end{aligned}$