The degree of the equation x² - 2x + 1 = x2 - 3 is
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Step-by-step explanation:
x2−2x+1=0
⟹(x)2−(2×x×1)+(1)2=0
⟹(x−1)2=0
[∵a2−2ab+b2=(a−b)2]
⟹(x−1)(x−1)=0
⟹x=1,1
or
x^2–2x+1
by splitting this equation
x^2-x-x+1
there are a two terms x^2-x and -x+1
we take x is common from first and -1 is common from second
x(x-1) and -1(x-1)
the quadratic roots are (x-1) and (x-1)
x-1=0
x=1 in both
So the quadratic roots are 1,1
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Given equation
= X2 –2x +1 =X2 – 3
X2– X2 –2x+ 1+3=0
2x+4=0
so degree of the equation are........ 1
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