Question

The denominator of a fraction exceeds its numerator by 8. if the numerator is increased​

Answer 1

Step-by-step explanation:

Let the numerator be x

We are given that the denominator of a fraction exceeds its numerator by 8

So, Denominator = x+8

$Original \: Fraction =\frac{x}{x+8}$

Now we are given that the numerator is increase by 17 and the denominator is decreased by 1 So, we get 3:2

$So, \frac{x+17}{x+8-1}=\frac{3}{2} </p><p>\frac{x+17}{x+7}=\frac{3}{2}$

2x+34=3x+212x+34=3x+21

34-21=x34−21=x

13=x13=x

$So, \: Original \: Fraction =\frac{13}{13+8}=\frac{13}{21} \\ Hence \: the \: original \: fraction \: is \: \frac{13}{21} </p><p>$