the denominator of a fraction is 1 more thn twice its numerator. if the numerator and denomnatr are both incresed by 5.. it becomes 3/5 .. find the original fraction
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let the numerator =x
denominator =2x+1
fraction =x/2x+1----(1)
if the numerator and denominator ate both increased by 5 =3/5
(x+5)/(2x+1+5)=3/5
(x+5)/(2x+6)=3/5
5(x+5)=3(2x+6)
5x+25=6x+18
25-18=6x-5x
7=x
x=7
substitute. x=7 in (1)
required fraction=x/(2x+1)
=7/(2*7+1)
=7/15
denominator =2x+1
fraction =x/2x+1----(1)
if the numerator and denominator ate both increased by 5 =3/5
(x+5)/(2x+1+5)=3/5
(x+5)/(2x+6)=3/5
5(x+5)=3(2x+6)
5x+25=6x+18
25-18=6x-5x
7=x
x=7
substitute. x=7 in (1)
required fraction=x/(2x+1)
=7/(2*7+1)
=7/15
Anonymous:
how do u get 3/5
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