Question

The denominator of a fraction is greater than the numerator by 8. If the
numerator is increased by 17 and denominator is decreased by 1, the number
obtained is 5/3. Find the fraction.

Class 8 Maths Chapter Linear Equvation.

Answer 1

Answer:

Let numerator and denominator be x and y.

Therefore,

required fraction = x/ y

Now,

Case 1

y= x+8

Case 2

x+17/y-1=5/3

Now, we will put the value of y from case 1

Therefore,

x+17/x+8-1=5/3

x+17/x+7=5/3

3x+51=5x+35

51-35=5x-3x

16=2x

x=16/2

x=8

On putting x=8 in case 1, we get

y= x+8

y=8+8

y=16

Hence,

required fraction=8/16=1/2

Answer 2

Answer:

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Step-by-step explanation:

hope you understand