Question

the denominator of a rational number is greater than its numerator by 10 if the numerator is increased by 19 and the denominator is decreased by 1 the number obtained is 3/2. find the rational no​

Answer 1

Let the numerator be x, and denominator be y.

A/q,

$x + 10 = y \\ x + y = - 10....1 \\ x + 19 + y - 1 = - 10 \\x + 18 + y = - 10 \\ x + y = - 10 - 18 \\ x + y = - 28.....2 \\ \\ subtracting \: eq \: 1 \: from \: 2$

$x + y = - 28 \\ x - y = - 10 \\ x = - 38 \\ putting \: the \: value \: of \: x \: in \: equation \: 1 \: we \: get$

x+y= -10

-38 +y =-10

y= -10+38

y=28

So the fraction is -28/38

hope it helps..