Question

The denominator of a rational number is greater than its numertor by 4 .if the numberator is increased by 11 and the denominator is increased by 1, the number oftained is 7/3 .find the rational number

Answer 1

Let numerator = x
Denominator = x + 4

$fraction \: = \frac{x }{x + 4}$


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if the numberator is increased by 11 and the denominator is increased by 1,

Then,

$\frac{x + 11}{x + 4 + 1} = \frac{7}{3} \\ \\ \frac{x + 11}{x + 5} = \frac{7}{3} \\ \\ 3(x + 11) = 7(x + 5) \\ \\ 3x + 33 = 7x + 35 \\ \\ 33 - 35 = 7x - 3x \\ \\ - 2 = 4x \\ \\ x = - \frac{2}{4} \\ \\ x = - \frac{1}{2} \\ \\ fraction \: => \frac{ - \frac{1}{2} }{ - \frac{1}{2} +4 } = > \frac{ - \frac{1}{2} }{ \frac{ - 1 + 8}{2} } \\ \\ \frac{ - \frac{1}{2} }{ \frac{7}{2} } \\ \\ - \frac{1}{7} \\ \\ \\ original \: fraction \: =$



I hope this will help you



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Answer 2

Heya ✋

Let see your answer !!!!!

Let the numerator be x. Then,

denominator = x + 4.

According to question ,

x + 11 / x + 4 + 1 = 7/3

=> x + 11 / x + 5 = 7/3

=> 3(x + 11) = 7(x + 5)

=> 3x + 33 = 7x + 35

=> 3x - 7x = 35 - 33

=> - 4x = 2

=> x = 2/ -4

=> x = -1/2

Hence ,

$numerator \: = \frac{ - 1}{2} \\ denominator \: = \frac{ - 1}{2} + 4 \\ = \frac{ - 1 + 8}{2} \\ = \frac{7}{2}$

$original \: fraction \: = \frac{ - 1}{2} \div \frac{7}{2} \\ = \frac{ - 1}{2} \times \frac{2}{7} \\ = \frac{ - 1}{7}$








Thanks :))))))